Answered

Get personalized answers to your specific questions with IDNLearn.com. Ask anything and receive thorough, reliable answers from our community of experienced professionals.

A gyroscope flywheel of radius 2.12 cm is accelerated from rest at 16.2 rad/s2 until its angular speed is 1820 rev/min. (a) what is the tangential acceleration of a point on the rim of the flywheel during this spin-up process

Sagot :

Asuwafohjamesidn

The tangental acceleration of the flywheel of  radius 2.12 cm with a final angular velocity of 1820 rev/min and an angular acceleration of 16.2 rad/s is 0.34 m/s².

What is tangental acceleration?

This is the rate of change of tangental velocity of an object in circular motion.

To calculate the tangental acceleration, we use the formula below.

Formula:

  • a = αr............. Equation 1

Where:

  • a = Tangental acceleration
  • r = radius of the flywheel
  • α = Angular acceleration of the flywheel.

From the question,

Given:

  • r = 2.12 cm = 0.0212 m
  • α = 16.2 rad/s²

Subsitute these values into equation 1

  • a = (0.0212×16.2)
  • a = 0.34 m/s²

Hence, The tangental acceleration of the flywheel of  radius 2.12 cm with a final angular velocity of 1820 rev/min and an angular acceleration of 16.2 rad/s is 0.34 m/s².

Learn more about tangental acceleration here: https://brainly.com/question/11476496

We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Thank you for trusting IDNLearn.com. We’re dedicated to providing accurate answers, so visit us again for more solutions.