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Answered

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For any value of x, the sum
3
∑ k(2x-1)
k=0
is equivalent to

Sagot :

Abidemiokinidn

The equivalent value of the sum for any value of "x" is 12x - 6

How to find the sum of functions?

Given the sum of the expression as:

3

∑ k(2x-1)

k=0

We need to take the sum of the function at the point where k = 0 to 3

3

∑ k(2x-1) = 0(2x-1) + 1(2x - 1) + 2(2x-1) + 3(2x - 1)

k=0

3

∑ k(2x-1) = 2x-1+4x-2+6x-3

k=0

3

∑ k(2x-1) = 12x - 6

k=0

Hence the equivalent value of the sum for any value of "x" is 12x - 6

Learn more on sum functions here: https://brainly.com/question/24295771

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