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Sagot :
Semi perimeter:-
[tex]\\ \rm\rightarrowtail s=\dfrac{a+b+c}{2}[/tex]
[tex]\\ \rm\rightarrowtail s=\dfrac{1.8+2.4+3}{2}[/tex]
[tex]\\ \rm\rightarrowtail s=\dfrac{7.2}{2}=3.6cm[/tex]
Apply heron s formula
Area:-
[tex]\\ \rm\rightarrowtail \sqrt{s(s-a)(s-b)(s-c)}[/tex]
[tex]\\ \rm\rightarrowtail \sqrt{3.6(3.6-1.8)(3.6-3)(3.6-2.4)}[/tex]
[tex]\\ \rm\rightarrowtail \sqrt{3.6(1.8)(0.6)(1.2)}[/tex]
[tex]\\ \rm\rightarrowtail \sqrt{4.6656}[/tex]
[tex]\\ \rm\rightarrowtail 2.16cm^2[/tex]
Answer:
[tex]\sf Area \ of \ a \ Triangle=\dfrac12bh[/tex]
(where b is the base of the triangle and h is the height)
Given:
- base = 2.4 cm
- height = 1.8 cm
Substitute the given values into the formula:
[tex]\sf \implies Area=\dfrac12 \cdot 2.4 \cdot 1.8[/tex]
[tex]\sf =2.16 \ cm^2[/tex]
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