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Find the surface area.
9 in
7 in
16 in

Find The Surface Area 9 In 7 In 16 In class=

Sagot :

Spbankingandsscserieidn

❀ Explanation -:

In this question we are provided with the length breadth and height and we are asked to find the surface area of the figure.

[tex] \small\bf{ Length = 16 \: inches } \\ \small\bf{Breadth = 7 \: inches} \\ \small\bf{Height = \: 9 \: inches} [/tex]

We know,

[tex] \pink\star \: \large\boxed{ \pink{ \rm{ Surface \: area = 2(lb + bh + hl)}}}[/tex]

Substituting the values we get

Surface area = 2(16 × 7 + 7 × 9 + 9 × 16)

= 2(112 + 63 + 144)

= 2(319)

= 638

Surface area = 638 inches².

TheAmethystidn

Hey !

Question :

Find the surface area of cuboid .

Given :

  • Length of Cuboid = 16 inches

  • Breadth of Cuboid = 7 inches

  • Height of Cuboid = 9 inches

To Find :

  • We have to find the surface area of given cuboid .

Concept :

The concept of this question belongs to surface areas of different three dimensional shapes . Whether they are cuboid , cube , cylinder , cone and many more .

Formula Used :

[tex] \boxed{\sf{ \pink{Surface \: Area \: of \: cuboid=} \pink{2(lw + wh + hl)}}}[/tex]

Where ,

  • l = length height of cuboid

  • w = width height of cuboid

  • h = height of cuboid

So Starting Our Solution :

Substituting value in formula ,

[tex] \longmapsto \: 2 ((16 \times 7) + (7 \times 9) + 9 \times 16)[/tex]

Now ,

[tex] \longmapsto \: 2(112 + 63 + 144)[/tex]

Adding the values which are inside bracket ,

[tex] \longmapsto \: 2(319)[/tex]

Now multiplying 319 by 2 ,

[tex] \longmapsto \: \bold{ 638 \: inches {}^{2} }[/tex]

Therefore ,

[tex] \boxed{ \sf \pink{Surface \: area \: of cuboid = 638 \: in {}^{2} }}[/tex]

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