Get the answers you've been looking for with the help of IDNLearn.com's expert community. Join our interactive community and get comprehensive, reliable answers to all your questions.
Sagot :
(1) The time taken for the drag racer to accelerate is 4.89 s
(2) The speed of the contestant (a) in feet per second is 30.89 ft/s (b) in miles per hr is 21.12 miles per hr.
(1) To calculate the time required to accelerate 18 ft/sec² from rest to a velocity of 60 mph, we use the formula below.
Formula:
- t = (v-u)/a........... Equation 1
Where:
- t = time
- v = Final velocity
- u = initial velocity
- a = acceleration.
From the question,
Given:
- a = 18 ft/sec² = (18×0.3048) = 5.4864 m/s²
- v = 60 mph = (60×0.44704) = 26.82 m/s
- u = 0 m/s ( from rest)
Substitute these values into equation 1
- t = (26.82-0)/5.4864
- t = 4.89 seconds
(2) To calculate the speed of the contestant, we use the formula below
Formula:
- s = d/t............ Equation 1
Where:
- s = speed of the contestant
- d = distance
- t = time.
From the question,
Given:
- d = 100 m
- t = 10.6 s
Substitute these values into equation 1
- s = 100/10.6
- s = 9.43 m/s
(a) In feet = (9.43/0.3048) = 30.94 ft/s
(b) in miles per hr = (9.43×2.24) = 21.12 miles per hr
Hence, (1) The time taken for the drag racer to accelerate is 4.89 s (2) The speed of the contestant (a) in feet per second is 30.89 ft/s (b) in miles per hr is 21.12 miles per hr.
Learn more about speed here: https://brainly.com/question/4931057
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. For dependable and accurate answers, visit IDNLearn.com. Thanks for visiting, and see you next time for more helpful information.