[tex]3^{x-2} = \left(\dfrac 13 \right)^{\sqrt x}\\ \\\implies 3^{x -2} = \left(3^{-1} \right)^{\sqrt x} \\\\\implies 3^{x-2} = 3^{-\sqrt x}\\\\\implies x -2 = -\sqrt x\\\\\implies (x-2)^2 = \left(-\sqrt x \right)^2\\\\\implies x^2 -4x +4 = x\\\\\implies x^2 -5x +4 =0\\\\\implies x^2 -4x-x+4=0\\\\\implies x(x-4) -(x-4)=0\\\\\implies (x-1)(x-4)=0\\\\\implies x = 1~~~~~~;[x = 4 ~ \text{Does not satisfy the original equation}]\\\\\text{Hence, x =1 is the solution.}[/tex]
