Answer:
Step-by-step explanation:
(1 , -2) x₁ =1 & y₁ = -2
(-3,10) x₂= -3 & y₂ = 10
First we need to find the slope.
[tex]\boxed{Slope = $\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$}[/tex][tex]\boxed{Slope=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}}[/tex]
[tex]=\dfrac{10-[-2]}{-3-1}\\\\\\=\dfrac{10+2}{-4}\\\\\\=\dfrac{12}{-4}\\\\\\= - 3[/tex]
m = -3
Equation of the line: y = mx + b
y = -3x + b
To find the value of b, take one of the point and substitue in the above equaiton.
(1 , -2)
-2 = -3*1 + b
-2 = -3 + b
-2 + 3 = b
b = 1
Equation of the line:
y = -3x + 1
