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what force much be applied to stop a 1400kg car that is initially traveling at 13 m/s over a 5 second time period

Sagot :

Answer:

As per Provided Information

  • Mass of car m is 1400Kg
  • Initial velocity u is 13m/s
  • Time taken to stop t is 5 second .
  • Final velocity v is 0m/s

we have been asked to determine the force applied to stop the car. First we will calculate the acceleration of the car.

[tex] \boxed{\bf \: a \: = \dfrac{(v - u)}{t}}[/tex]

Substituting the value and let's solve it

[tex] \longrightarrow\sf \: a \: = \dfrac{0 - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = \cfrac{ - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = - 2.6 \: {ms}^{ - 2} [/tex]

Now, let's calculate the force applied to stop the car .

[tex] \pink{\boxed{\bf \: F = ma}}[/tex]

Substituting the value we get

[tex] \longrightarrow \sf \: F = 1400 \times ( - 2.6) \\ \\ \\ \longrightarrow \sf \: F = - 3640 \: N[/tex]

Here , negative sign show that the " Force is acting in opposite direction of the motion"

Therefore,

  • 3640 Newton force is required to stop the car .

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