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Graphing f(x)=(x+2)^2-3 in vertex form

Sagot :

Answer:

Step-by-step explanation:

This is a parabola shaped like a U.

The minimum value is at (-2, -3).

Find the zeroes:

(x + 2)^2 = 3

Find the zeroes:

x + 2 = +/- √3

x = +/-√3 - 2

x = -0.27, -3.73.

So the graph cuts the x axis at (-0.27, 0)  and (-3.73, 0)

when x = -4 , f(x) = 1 and when x = 1,  f(x) =  6.

So you can now draw the curve through these 5 points and it will be shaped like a U, symetrical about the line x = -2

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