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Write an equation for the line that passes through (−8.5,11) and (5,−2.5)

Write An Equation For The Line That Passes Through 8511 And 525 class=

Sagot :

Fieryanswererftidn

y = -x + 2.5

slope formula:

[tex]\sf \dfrac{y_2-y_1}{x_2-x_1}[/tex]

find slope:

[tex]\rightarrow \sf \dfrac{-2.5-11}{5-(-8.5)}[/tex]

[tex]\rightarrow \sf \dfrac{-13.5}{13.5}[/tex]

[tex]\rightarrow \sf -1[/tex]

equation formula:

[tex]\sf y_1-y = m(x_1-x)[/tex]

find equation:

[tex]\hookrightarrow \sf y-11=-1(x-(-8.5)[/tex]

[tex]\hookrightarrow \sf y-11=-x-8.5[/tex]

[tex]\hookrightarrow \sf y=-x-8.5+11[/tex]

[tex]\hookrightarrow \sf y=-x+2.5[/tex]
  • (-8.5,11)
  • (5,-2.5)

Slope:-

  • m=-2.5-11/5+8.5
  • m=-13.5/13.5
  • m=-1

Equation in point slope form

  • y-11=-1(x+8.5)
  • y-11=-x-8.5
  • y=-x+2.5
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