Answered

Explore IDNLearn.com to discover insightful answers from experts and enthusiasts alike. Discover reliable and timely information on any topic from our network of experienced professionals.

A spring with spring constant 0.5 m has a force of 40 newtons applied to it. How much does the spring
stretch? Use Hooke's law F = kx
N
O A 1,600 cm
OB. 100 cm
O C. 80 cm
O D. 40 cm

Sagot :

Abidemiokinidn

The spring stretch by 80cm if a spring constant 0.5 m has a force of 40 newtons applied to it

How to calculate the force acting on string?

According to Hookes law

F = ke

where

F is the applied force = 40N

k is the spring constant

e is the extension  = 0.5

Substitute

40 = 0.5e

e = 40/0.5

e = 80cm

Hence the spring stretch by 80cm if a spring constant 0.5 m has a force of 40 newtons applied to it

Learn more on hookes law here: https://brainly.com/question/12253978

Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.