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What is the y intercept of the equation-16x^2+64x+80?
The y-intercept is the value of the function when x=0. For a polynomial in x, setting x=0 effectively eliminates all of the variable terms, leaving only the constant term.
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The y-intercept is the constant: 80. The coordinates of the y-intercept point reflect the fact that x=0 there: (0, 80).
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