Answer:
Assuming the area is made up of a square and a semicircle.
Perimeter
The side length of the square = 18 ft
We can see 3 full side lengths plus one side length from which we need to subtract 12 ft (see attached diagram).
⇒ perimeter of the square = (3 x 18) + (18 - 12)
= 54 + 6
= 60 ft
Circumference of a circle = [tex]\pi[/tex]d (where d is the diameter)
⇒ arc length of the semicircle = 1/2 circumference
= 1/2 · [tex]\pi[/tex] · 12
= 6[tex]\pi[/tex] ft
Total perimeter = 60 + 6[tex]\pi[/tex] = 78.8 ft (nearest tenth)
Area
Area of a square = s² (where s is the side length)
⇒ area of square = 18²
= 324 ft²
Diameter = 2r ⇒ r = 1/2 diameter
Area of a circle = [tex]\pi[/tex]r² (where r is the radius)
⇒ area of the semicircle = 1/2 · [tex]\pi[/tex] · 6²
= 18[tex]\pi[/tex] ft²
Total area = 324 + 18[tex]\pi[/tex] = 380.5 ft² (nearest tenth)
