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A cart weighing 200 pounds rests on an incline at an angle of 40 degrees. what is the required force to keep the cart at rest? round to the thousandths place

a) 128.558 pounds
b) 133.388 pounds
c) 149.023 pounds
d) 153.208 pounds

Sagot :

Samuelonum1idn

The force needed to keep the cart at rest is 149.022 pounds

Force and Motion

Given Data

  • Weight of cart = 200 pounds
  • Angle = 40 degree

The force needed to keep the cart at rest is the vertical component of the resultant force, hence we have

Fy = Mg sin θ

Substituting our given data we have

Fy = 200 sin 40

Fy = 200 *0.74511

Fy = 149.022 pounds

Learn more about force here:

https://brainly.com/question/12970081

Answer:

128.558

Step-by-step explanation:

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