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An astronaut lands on another planet and wishes to determine the acceleration due to gravity.the astronaut measure a period of 0.5m pendulum as being 3.2 seconds what is the acceleration due to gravity

Sagot :

Answer:

1.927  m/s^2

Explanation:

period = 2 pi  sqrt ( l/g)  

3.2   =  2 pi sqrt (.5/g) =1.927 m/s^2

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