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and right triangle sin (40 - x)° equals cos(3x)° degrees what is the value of x.

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[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: \sin(40 - x) = \cos(3x) [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cos\{90 - (40 - x ) \} = \cos(3x) [/tex]

[tex]\qquad \sf  \dashrightarrow \:90 - (40 - x) = 3x[/tex]

[tex]\qquad \sf  \dashrightarrow \:90 - 40 + x = 3x[/tex]

[tex]\qquad \sf  \dashrightarrow \:3x - x = 50[/tex]

[tex]\qquad \sf  \dashrightarrow \:2x = 50[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 25 \degree[/tex]

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