IDNLearn.com: Your go-to resource for finding precise and accurate answers. Get step-by-step guidance for all your technical questions from our knowledgeable community members.
Sagot :
The solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L
Effect of Pressure on Solubility
As the pressure of a gas increases, the solubility increases, and as the pressure of a gas decreases, the solubility decreases.
Thus, Solubility varies directly with Pressure
If S represents Solubility and P represents Pressure,
Then we can write that
S ∝ P
Introducing proportionality constant, k
S = kP
S/P = k
∴ We can write that
[tex]\frac{S_{1} }{P_{1} } = \frac{S_{2} }{P_{2} }[/tex]
Where [tex]S_{1}[/tex] is the initial solubility
[tex]P_{1}[/tex] is the initial pressure
[tex]S_{2}[/tex] is the final solubility
[tex]P_{2}[/tex] is the final pressure
From the given information
[tex]S_{1} = 0.890 \ g/L[/tex]
[tex]P_{1} = 120 \ kPa[/tex]
[tex]P_{2} = 100 \ kPa[/tex]
Putting the parameters into the formula, we get
[tex]\frac{0.890}{120}=\frac{S_{2}}{100}[/tex]
[tex]S_{2}= \frac{0.890 \times 100}{120}[/tex]
[tex]S_{2}= 0.742 \ g/L[/tex]
Hence, the solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L
Learn more on Solubility here: https://brainly.com/question/4529762
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your questions are important to us at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.
