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A 750-m section of river runs parallel to a channel 1,000 m away. an aquifer connecting the two has hydraulic conductivity equal to 7. 0 m/day and an average thickness of 10 m. the surface of the river is 5. 0 m higher than the surface of the channel. estimate the rate of seepage (qseepage) from the river to the channel

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Ogorwyneidn

Given a 750 m section with distance of 1000m , The calculated rate of seepage from the river to the channel has been calculated to be 262.5 m³/day.

What is the rate of seepage?

This is the calculated rate that shows how water is infiltrated downward into the soil.

The formula is given as

[tex]Q = KA \frac{dh}{dl}[/tex]

A = Area = 750*10 = 7500m

dh = h₂-h₁

= 10 - 5 = 5m

dl = 1000m

[tex]Q = 7*7500*\frac{5}{1000}[/tex]

= 262.5m³

The rate of seepage from the calculation above is  262.5m³.

Read more on rate of seepage: https://brainly.com/question/21499824

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