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The amplitude of this graph is 3 the maximum is 4 the minimum is -2 the period is 4 and the midline is 1 how would the function be written is all I haven’t figured out

The Amplitude Of This Graph Is 3 The Maximum Is 4 The Minimum Is 2 The Period Is 4 And The Midline Is 1 How Would The Function Be Written Is All I Havent Figure class=

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[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

The required equation is :

[tex] \qquad \sf  \dashrightarrow \:y = a \sin(bx) + k[/tex]

Now, let's find the required values :

period (p) = 4

[distance between any successive Crest or trough]

a = - 3 (flipped)

b = 2π/p = 2π/4 = π/2

k = 1

Distance of starting position from origin = k

Now, plug in the values ~

[tex]\qquad \sf  \dashrightarrow \: - 3 \sin( \frac{ \pi}{2}x ) + 1[/tex]

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