Given :
- An angle which measures 26.8° less than the measure of its complementary angle.
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To Find :
- The measure of each angle.
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Solution :
- Let's assume the one of the complementary angle as "x" and the other angle as (x – 26.8)° .
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Now,
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According to the Question :
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[tex]{\longrightarrow \qquad \sf{ x + {(x - 26.8)}^{ \circ} = {90}^{ \circ} }}[/tex]
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[tex]{\longrightarrow \qquad \sf{ x + {x - 26.8}^{ \circ} = {90}^{ \circ} }}[/tex]
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[tex]{\longrightarrow \qquad \sf{ 2 {x - 26.8}^{ \circ} = {90}^{ \circ} }}[/tex]
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[tex]{\longrightarrow \qquad \sf{ 2 x = {90}^{ \circ} + 26.8^{ \circ}}}[/tex]
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[tex]{\longrightarrow \qquad \sf{ 2 x = 116.8^{ \circ}}}[/tex]
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[tex]{\longrightarrow \qquad \sf{ x = \dfrac{116.8^{ \circ}}{2}}}[/tex]
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[tex]{\longrightarrow \qquad \frak{\pmb{ x =58.4^{ \circ}}}}[/tex]
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Therefore,
- Other angle = 58.4° – 26.8° = 31.6°
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Hence,
- The measure of the each angles are 58.4° and 31.6° .