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[tex] \rm{3(2x-5)=4x+33} \\ \\ \rm {solving \: bracket} \\ \\ \rm{6x - 15= 4x + 33} \\ \\ \rm{arranging \: terms} \\ \\ \rm{6x - 4x = 33 + 15} \\ \\ \rm{2x = 48} \\ \\ \rm{x = \frac{48}{2} } \\ \\ \rm{x = \cancel \frac{48}{2} } \\ \\ \rm{x = 24}[/tex]
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Answer:
[tex]\fbox{X = 24}[/tex]
Solution:
Given expression ➟ 3(2x-5) = 4x + 33,
using distributive property open the above bracket,
➳ 3×2x - 3×5 = 4x + 33
Using BODMAS solve the L.H.S,
➳ 6x - 15 = 4x + 33
now arrange the like terms aside,
➳ 6x - 4x = 33 + 15
➳ 2x = 48
➳ x = 48/2
➳ x = 24
the given expression is true for x = 24
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