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Sagot :
vertex : (1,-3)
coordinates : (3,1) and (-1,1)
parabola formula : y = a(x -h)² + k
- (x, y) - from the coordinates
- (h, k) - from the vertex
so given,
h = 1
k = -3
x = 3
y = 1
solve for a:
- 1 = a(3 -1)² + (-3)
- 1 = 4(a) - 3
- 4(a) = 4
- a = 1
Therefore equation:
y = (x -1)² - 3
check the graph for confirmation:
Answer: Graph the parabola y=x2−7x+2 .
Compare the equation with y=ax2+bx+c to find the values of a , b , and c .
Here, a=1,b=−7 and c=2 .
Use the values of the coefficients to write the equation of axis of symmetry .
The graph of a quadratic equation in the form y=ax2+bx+c has as its axis of symmetry the line x=−b2a . So, the equation of the axis of symmetry of the given parabola is x=−(−7)2(1) or x=72 .
Substitute x=72 in the equation to find the y -coordinate of the vertex.
y=(72)2−7(72)+2 =494−492+2 =49 − 98 + 84 =−414
Therefore, the coordinates of the vertex are (72,−414) .
Now, substitute a few more x -values in the equation to get the corresponding y -values.
x y=x2−7x+2
0 2
1 −4
2 −8
3 −10
5 −8
7 2
Plot the points and join them to get the parabola
in short terms D.
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