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For an airplane whose speed is 60 m/s is flying at an altitude of 500 m over the ocean toward a stationary sinking ship, the horizontal distance is mathematically given as
x=606m
Generally, the equation for the y axis distance is mathematically given as
y=vt+0.5gt^2
Therefore
500=0t+1.2(9.8)t^2
t=10.1s
In conclusion, the horizontal distance
x=vt
x=60*10.1
x=606m
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