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In a steam engine, steam in a cylinder expands against a piston, exerting 10 atm of external pressure. The volume of the cylinder increases by 10 L and simultaneously the steam cools, losing 3,000 kJ of energy to the surroundings. What is the change in energy of the steam

Sagot :

If steam in a cylinder expands against a piston, exerting 10 atm of external pressure, the change in energy of the steam is mathematically given as

dE= -3010 kJ

What is the change in energy of the steam?

Generally, the equation for the workdone  is mathematically given as

Work = - (pressure * Volume)

Therefore

w= - (10 x 10)

w= -100 L atm

In conclusion

dEnergy = q + work

dE = -3000 + -10.13

dE= -3010 kJ

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