Answered

Get the most out of your questions with the extensive resources available on IDNLearn.com. Discover in-depth answers from knowledgeable professionals, providing you with the information you need.

The concentration of A is initially 0.150 M before it proceeds to equilibrium. The system is at 298 K. What is the equilibrium concentration of B

Sagot :

Okpalawalter8idn

For a  concentration of  is initially 0.150 M before it proceeds to equilibrium, the equilibrium concentration of B  is mathematically given as

x=3.0*10^{-7}m

What is the equilibrium concentration of B?

Generally, the equation for the  change in Gibbs free energy   is mathematically given as

dG=-RTInK

Therefore

31.5*10*^{3}=-(8.314)(298)(ink)

K=3*10^(-6)

Eqution

A--->B

K=x/0.1-x

x=3.0*10^{-7}m

In conclusion, the equilibrium concentration

x=3.0*10^{-7}m

Read more about Concentration

https://brainly.com/question/16979235

We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com has the answers you need. Thank you for visiting, and we look forward to helping you again soon.