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The optimal sizes of the brand of paint given a mean of 28 and standard deviation of 8 is 81. The reorder point of the paint is 124 while the optimal safety stock is 26.
How to solve for the optimal size
mean = 28
sd = 8
Replenishment = 14 weeks
convert to months = 3.5 months
paint = $6
mean = 28 x 3.5
= 98
Find the standard deviation
= 8 x sqr(3.5)
= 14.966 = 15
Mean rate of demand
12 x 28 = 336
cost of holding = 30% x 6 = 1.8
unfilled demand = $10
EOQ = 2x 336 x 15 /1.8
= 5600
[tex]\sqrt{5600} = 75[/tex]
R0 = [tex]\frac{75*1.8}{10*336} = 0.04[/tex]
From the z table, 0.04 = 1.75
15x1.75x98 = 124.35
σLz = 0.242
Q1 = [tex]\sqrt{\frac{2*336}{1.8}(15+10)(0.2426) }[/tex]
= 81
81x1.8/10x336
= 0.043
How to solve for the reorder point
If R1 = 0.043 z value would be 1.75
15 x 1.75 + 98
= 124.3
R0 = R1
Q,R = (81, 124)
the optimal lot sizes = 81.
reorder points = 124
How to solve for the optimal safety stock
R - mean
124 - 98
= 26
Read more on optimal safety stock https://brainly.com/question/14054595
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