Answer:
7.2224
Step-by-step explanation:
The value of the summation is given by the formula ...
Sn = (a1)(1 -r^n)/(1 -r) . . . . . where a1 is the first of n terms, and r is the common ratio.
Your sum has first term and ratio ...
a1 = 2(0.6) . . . . . summation term for n=1
r = 0.6
So the sum is ...
[tex]\displaystyle \sum_{n=1}^4{2(0.6^n)}=2(0.6)\dfrac{1-0.6^4}{1-0.6}=\dfrac{1.2}{0.4}(0.8704) = 2.6112[/tex]
Then the value of the entire given expression is ...
[tex]\displaystyle 2+2\sum_{n=1}^4{}2(0.6^n)=2+2(2.6112)=\boxed{7.2224}[/tex]
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A calculator can help you find the value.
