IDNLearn.com offers a comprehensive solution for finding accurate answers quickly. Our experts provide prompt and accurate answers to help you make informed decisions on any topic.
The minimum mass of Zinc, Zn that needs to be added to 0.500 g of iodine so that the iodine fully reacts is 0.128 g
Zn + I₂ —> ZnI₂
Molar mass of Zn = 65 g/mol
Mass of Zn from the balanced equation = 1 × 65 = 65 g
Molar mass of I₂ = 127 × 2 = 254 g/mol
Mass of I₂ from the balanced equation = 1 254 = 254 g
SUMMARY
From the balanced equation above,
254 g of I₂ required 65 g of Zn
From the balanced equation above,
254 g of I₂ required 65 g of Zn
Therefore,
0.5 g of I₂ will require = (0.5 × 65) / 254 = 0.128 g of Zn
Thus, the minimum mass of Zn required is 0.128 g
Learn more about stoichiometry:
https://brainly.com/question/14735801