Answered

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Two particles each with a charge of 1μC are separated a distance of 0.4 m. A test charge is placed just above them but directly between them. (b) What is the direction of the resultant electric field on the test charge?

Sagot :

Answer:

Forces on the test (test is positive) charge

Σ Fx = 0       net result of x-compoment charges is zero

Σ Fy = 2 F sin θ      where F is the force due to the distance of the test charge from one of the charges and sin θ  is the component of that force that is perpendicular to the line separating the charges

The direction of the force is perpendicular to the line separating the two given charges

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