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When a 21.2 mL sample of a 0.411 M aqueous hydrofluoric acid solution is titrated with a 0.371 M aqueous barium hydroxide solution, what is the pH after 17.6 mL of barium hydroxide have been added

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For a 21.2 mL sample of a 0.411 M aqueous hydrofluoric acid solution,  the pH after 17.6 mL of barium hydroxide has been added is mathematically given as

pH=3.332

What is the pH after 17.6 mL of barium hydroxide has been added?

Generally, the equation for the  mole of HF is mathematically given as

mole of HF=molarity*volume

Therefore

mole of HF=0.361*19.2

mole of HF=6.931mmol

The chemical equation

HF+kOH⇆KF+H2O

Therefore

pH=pKa+log(Kf/HF)

pH=3.15+log(6.931*53.6/53.6*4.558)

pH=3.332

In conclusion, The pH

pH=3.332

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