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Write the equation in point-slope form. (4,-2) ; m=1/2

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Loneguyidn

[tex]\text{Given that,}\\\\(x_1,y_1) = (4,-2)~~ \text{and slope,}~ m =\dfrac 12\\\\\text{Point - slope form,}\\\\y-y_1 = m(x-x_1)\\\\\implies y -(-2) = \dfrac 12(x-4)\\\\\implies y+2=\dfrac 12(x-4)[/tex]

Zyilin4idn

(4,-2) are points [tex](x_1, y_1)[/tex] respectively and [tex]\frac{1}{2}[/tex] is the slope

Point-slope:

[tex]y-y_1 = m(x-x_1)[/tex]      

Now you have to replace the variables with numbers

[tex]y+2 = \frac{1}{2}(x-4)[/tex]

Thus your equation would be:

[tex]y+2 = \frac{1}{2}(x-4)[/tex]

Hope this helped!

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