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The value of the cox will be equal to Cosx=[tex]\pm[/tex]0.95
It is given that
The value of Sinx=0.3
Now we know that
[tex]Sin^2x+Cos^2x=1\\\\0.3^2+Cos^2=1\\\\Cos^2=1-0.3^2\\\\Cos^2x=1-0.9\\\\Cos^x=0.91\\\\Cos=\sqrt{0.91}\\\\Cosx=\pm 0.95[/tex]
Hence the value of Cosx=[tex]\pm[/tex]0.95
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