Answered

Find the best answers to your questions with the help of IDNLearn.com's expert contributors. Discover thorough and trustworthy answers from our community of knowledgeable professionals, tailored to meet your specific needs.

A firework is fired from the ground straight up on a planet with an acceleration due to gravity of 6.82 m/s/s. The firework will not explode until the moment where it would have started to move back down again. The initial speed of the firework is 69.5 m/s. Use this information to find the height at which the firework explodes and the time it will be traveling upward.

Sagot :

MAC186idn

Answer:

h = 384.4 m

t = 8.5 s

Explanation:

The firework will explode at the highest point. Because it would start to move downward at the highest point. Using 3rd equation of motion:

2ah = Vf² - Vi²

where,

a = acceleration due to gravity at that planet = -10.56 m/s²

h = maximum height = ?

Vf = Final velocity = 0 m/s (since, firework stops at highest point)

Vi = Initial Velocity = 90.1 m/s

Therefore,

2(-10.56 m/s²)(h) = (0 m/s)² - (90.1 m/s)²

h = 384.4 m

Now, we use 1st equation of motion:

Vf = Vi + at

0 m/s = 90.1 m/s + (-10.56 m/s²)(t)

t = 8.5 ss

Your presence in our community is highly appreciated. Keep sharing your insights and solutions. Together, we can build a rich and valuable knowledge resource for everyone. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.