well, we know its a rectangle, so hmmm opposite sides are not just parallel but equal, hmmm so the area of this rectangle we can get by Length * Width, in this case that'll be QT * TS
[tex]~~~~~~~~~~~~\textit{distance between 2 points} \\\\ Q(\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad T(\stackrel{x_2}{2}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ QT=\sqrt{[2 - 0]^2 + [-2 - 1]^2}\implies QT=\sqrt{2^2 + (-3)^2}\implies QT=\sqrt{13} \\\\[-0.35em] ~\dotfill[/tex]
[tex]T(\stackrel{x_1}{2}~,~\stackrel{y_1}{-2})\qquad S(\stackrel{x_2}{-7}~,~\stackrel{y_2}{-8})~\hfill TS=\sqrt{[-7 - 2]^2 + [-8 - (-2)]^2} \\\\\\ TS=\sqrt{(-9)^2 + (-8+2)^2}\implies TS=\sqrt{117} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{\sqrt{13}\cdot \sqrt{117}\implies \sqrt{1521}\implies 39}[/tex]
