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Sagot :
The period (T) of the right pendulum for small displacements in s is equal to 1.49 seconds.
How to calculate the period (T).
Mathematically, the time taken by this pendulum to undergo a small displacement is given by this formula:
[tex]T=2\pi \sqrt{\frac{L}{g} }[/tex]
Where:
- L is the length.
- g is the acceleration due to gravity.
Scientific data:
Acceleration due to gravity (g) = 9.8 m/s².
Assuming a randomized variable for the length of the rope to be 1.2 meter. Also, we know that the right pendulum has a radius of 1/2L.
1/2L = L/2
L/2 = 1.1/2
L/2 = 0.55 meter.
Substituting the parameters into the formula, we have;
[tex]T=2\times 3.142 \sqrt{\frac{0.55}{9.8} }\\\\T=6.284 \times \sqrt{0.0561} \\\\T=6.284 \times 0.2369[/tex]
T = 1.49 seconds.
Read more on a pendulum here: https://brainly.com/question/20070798

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