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if 6 coins are flipped, find the probability that there is at least one heads?
With 6 coins you times by 2 and minus by 1 again resulting in a 63 in 64 chance. To find the chance of getting at least one heads if you flip ten coins you times 64 by 2 four times or by 16 once and then minus 1, this results in a 1063 in 1064 chance of getting at least one heads.
If you for one coin it would be a 50% chance so you multiply that [tex]\frac{1}{2}^{6}[/tex] which would be the probability of no heads 1/64 and at least 1 head you would [tex]1-\frac{1}{64}[/tex] which is [tex]\frac{63}{64}[/tex]. Ask me if you have any further questions
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