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solve for b. a=1/2h (b+c)

Sagot :

[tex]a=\frac { 1 }{ 2 } h\left( b+c \right) \\ \\ \frac { 2 }{ h } \cdot a=\frac { 1 }{ 2 } h\cdot \frac { 2 }{ h } \left( b+c \right) \\ \\ \frac { 2a }{ h } =b+c\\ \\ b=\frac { 2a }{ h } -c[/tex]
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