Explore IDNLearn.com to discover insightful answers from experts and enthusiasts alike. Discover comprehensive answers from knowledgeable members of our community, covering a wide range of topics to meet all your informational needs.
Sagot :
Line 1:
[tex]x_1=-2 \\ y_1=-4 \\ \\ x_2=-1 \\ y_2=-1 \\ \\ m=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-(-4)}{-1-(-2)}=\frac{-1+4}{-1+2}=\frac{3}{1}=3 \\ \\ y=3x+b \\ (-1,-1) \\ -1=3 \times (-1)+b \\ -1=-3+b \\ -1+3=b \\ b=2 \\ \\ y=3x+2[/tex]
Line 2:
[tex]x_1=2 \\ y_1=3 \\ \\ x_2=3 \\ y_2=1 \\ \\ m=\frac{y_2-y_1}{x_2-x_1}=\frac{1-3}{3-2}=\frac{-2}{1}=-2 \\ \\ y=-2x+b \\ (3,1) \\ 1=-2 \times 3+b \\ 1=-6+b \\ 1+6=b \\ b=7 \\ \\ y=-2x+7[/tex]
The system of equations is:
[tex]y=3x+2 \\ y=-2x+7 \\ \\ y=y \\ 3x+2=-2x+7 \\ 3x+2x=7-2 \\ 5x=5 \\ x=\frac{5}{5} \\ x=1 \\ \\ y=3x+2=3 \times 1+2=3+2=5 \\ \\ \boxed{(x,y)=(1,5)}[/tex]
[tex]x_1=-2 \\ y_1=-4 \\ \\ x_2=-1 \\ y_2=-1 \\ \\ m=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-(-4)}{-1-(-2)}=\frac{-1+4}{-1+2}=\frac{3}{1}=3 \\ \\ y=3x+b \\ (-1,-1) \\ -1=3 \times (-1)+b \\ -1=-3+b \\ -1+3=b \\ b=2 \\ \\ y=3x+2[/tex]
Line 2:
[tex]x_1=2 \\ y_1=3 \\ \\ x_2=3 \\ y_2=1 \\ \\ m=\frac{y_2-y_1}{x_2-x_1}=\frac{1-3}{3-2}=\frac{-2}{1}=-2 \\ \\ y=-2x+b \\ (3,1) \\ 1=-2 \times 3+b \\ 1=-6+b \\ 1+6=b \\ b=7 \\ \\ y=-2x+7[/tex]
The system of equations is:
[tex]y=3x+2 \\ y=-2x+7 \\ \\ y=y \\ 3x+2=-2x+7 \\ 3x+2x=7-2 \\ 5x=5 \\ x=\frac{5}{5} \\ x=1 \\ \\ y=3x+2=3 \times 1+2=3+2=5 \\ \\ \boxed{(x,y)=(1,5)}[/tex]
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for solutions ends here at IDNLearn.com. Thank you for visiting, and come back soon for more helpful information.