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(09.04 LC)

A circle is centered at (7, 8) and has a radius of 11. Which of the following is the equation for this circle? (6 points)

(x − 7)2 + (y − 8)2 = 121

(x + 7)2 + (y + 8)2 = 121

(x + 7)2 + (y + 8)2 = 11

(x − 7)2 + (y − 8)2 = 11


Sagot :

Answer:

(x-7)^2+(y-8)^2=121

Step-by-step explanation:

View image Abdullahs84

The equation of a circle is centered at (7, 8) and has a radius of 11 [tex]\rm (x-7)^2+(y-8)^2=121[/tex].

What is the equation of a circle?

The circle equation formula refers to the equation of a circle which represents the center-radius form of the circle.

A circle can be represented as;

[tex]\rm (x-h)^2+(y-k)^2=r^2[/tex]

Where; h and k are the center of the circle r is the radius of the circle.

A circle is centered at (7, 8) and has a radius of 11.

The following is the equation for this circle is;

[tex]\rm (x-h)^2+(y-k)^2=r^2\\\\(x-7)^2+(y-8)^2=11^2\\\\(x-7)^2+(y-8)^2=121[/tex]

Hence, the equation of a circle is centered at (7, 8) and has a radius of 11 [tex]\rm (x-7)^2+(y-8)^2=121[/tex].

Learn more about circle here;

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