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Sagot :
The gram-formula mass of Sm is 150.36 u, and the gram-formula mass of O is 15.999 u, so the gram-formula mass of SmO is about 150.36+15.999 = 160.36 g/mol.
So, there are about (9.30 * 10^-3)(160.36)=1.49 grams
So, there are about (9.30 * 10^-3)(160.36)=1.49 grams
Molar mass of SmO or sodium methylate is 160g/mol
Now
- No of moles =Given mass /Molar mass
Given mass
- No of moles ×Molar mass
- 9.3×10^{-3}×160
- 1.488g
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