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If 96 as a product of its prime factors is 2x2x2x2x2x3, find the greatest common divisor of 72 and 96

Sagot :

Answer:

24

Step-by-step explanation:

72=2*2*2*3*3

96=2*2*2*2*2*3

Hcf=2*2*2*3=24#

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