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The vertical distance covered by a body falling freely under gravity is directly proportional to the square of the time for which it falls. If a body covers 300m in the first 10 seconds of its free fall, find the distance covered by the body in the next 10 seconds.​

Sagot :

Answer:

S = 1/2 a t^2       distance covered by falling body from speed = 0

300 = 1/2 a 10^2

a = 600 m / 100 s^2 = 6 m/s^2

v = a t = 6 m/s^2 s * 10 s = 60 m/s     speed after 10 sec

S2 = v t + 1/2 a t^2

S2 = 60 m/s * 10 sec + 3 m/s^2 * 100 s^2

S2 = 600  m + 300 m = 900 m

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