[tex]5x^{2}+|x+1|\ \textgreater \ 0[/tex]

Can someone explain me how this is done? My book says that the answer is R (all numbers), but i get [-1; infinity) and two other roots.

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01-05-2022
Mathematics

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[tex]5x^{2}+|x+1|\ \textgreater \ 0[/tex]

Can someone explain me how this is done? My book says that the answer is R (all numbers), but i get [-1; infinity) and two other roots.

Sagot :

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Alialakbar39idn Alialakbar39idn · Answer 1 · 2022-05-01T08:50:19-04:00

Alialakbar39idn Alialakbar39idn

01-05-2022

5x² + |x+1| > 0
5x² + x + 1 > 0
x+1 > 0 because it came from absolute
5x² > 0 because it’s squared

When you try a number you should put it in the original equality
5x² + |x+1|

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