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Find the volume, in cubic feet, of the solid with the regular base to the nearest tenth.

Find The Volume In Cubic Feet Of The Solid With The Regular Base To The Nearest Tenth class=

Sagot :

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Answer:

Step-by-step explanation:

Remark

The base of the figure is a pentagon

The area of the base of a pentagon is

A=(1/4) * √[5(5+2√5)] * s2

The Formula for the Volume of a "pyramid" of this nature is

Volume = Base * h / 3

 

Givens

h = 10 feet

s = 8 feet

Base = formula in the remark section

Solution.

Find the base first.

A=(1/4) * √[5(5+2√ 5)] * s2     Find the value of 5 + 2√5

Area = 0.25√[5*(9.47)] * s^2 Find what is under the root sign

Area = 0.25√47.36   * s^2     Take the square root of 47.36. use s = 8

Area = 0.25 * 6.88 * 8^2         Combine.

Area = 110.11

Now find the volume

V = B * h/3

V = 110.11 * 10 / 3

V = 367.04     cubic feet.

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