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Answer:
[tex]P_{CO_2} = 0.75 atm[/tex]
Explanation:
[tex]P_{total} = P_{CO} + P_{CO_2} + P_{N_2} + P_{O_2}[/tex]
Since there's equal molar amounts we can conclude that
[tex]P_{CO_2} = P_{CO} = P_{N_2} = P_{O_2}[/tex]
So,
[tex]P_{total} = 4P_{CO_2}\\3.00 atm = 4P_{CO_2}\\P_{CO_2} = \frac{3.00 atm}{4} = 0.75 atm[/tex]