Cat612idn
Answered

Join IDNLearn.com and start exploring the answers to your most pressing questions. Get prompt and accurate answers to your questions from our community of knowledgeable experts.

A 40kg cart gains a KE of 200J. How fast does it go?

Sagot :

Dad0ssidn

Answer:

3.16 m/s

Explanation:

Use the formula

[tex]k = \frac{m {v}^{2} }{2} \\ v = \sqrt{ \frac{2k}{m} } \\ v = \sqrt{ \frac{2(200)}{40} } \\ v = 3.16 \frac{m}{s} [/tex]

Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. Thank you for visiting IDNLearn.com. We’re here to provide accurate and reliable answers, so visit us again soon.