Answered

IDNLearn.com makes it easy to find answers and share knowledge with others. Our platform offers reliable and comprehensive answers to help you make informed decisions quickly and easily.

5. How much water would need to be added to 750 mL of a 2.8 M HCl solution to
make a 1.0 M solution?

6. If I add 25 mL of water to 125 mL of a 0.15 M NaOH solution, what will the molarity of the diluted solution be?

7. If I add water to 100 mL of a 0.15 M NaOH solution until the final volume is 150 mL, what will the molarity of the diluted solution be?

8. How much 0.05 M HCl solution can be made by diluting 250 mL of 10 M HCl?

9. I have 345 mL of a 1.5 M NaCl solution. If I boil the water until the volume of the solution is 250 mL, what will the molarity of the solution be?

10.
How much water would I need to add to 500 mL of a 2.4 M KCl solution to make a 1.0 M solution

please help me

Sagot :

The values of molarity and volumes for the given questions are  2,100 mL, 0.75 M, 0.1 M, 50,000 mL, 2.07 M and 1,200 mL respectively.

What is the relation between the molarity & volume of solution?

Relation between the molarity and volume of the solution will be shown by the following equation:
M₁V₁ = M₂V₂, where

M₁ & V₁ is the molarity and volume of one solution whereas M₂ & V₂ are the molarities and volume of the another solution.

  • Required volume of water needed to add at 750 mL of a 2.8 M HCl solution to make a 1.0 M solution will be calculated by using the above formula:

V₂ = (750)(2.8) / (1) = 2,100 mL

  • Required molarity of diluted solution obtained on adding 25 mL of water to 125 mL of a 0.15 M NaOH solution will be calculated by using the above formula:

M₂ = (0.15)(125) / (25) = 0.75 M

  • Required molarity of diluted solution obtained on adding 100 mL of a 0.15 M NaOH solution until the final volume is 150 mL will be calculated by using the above formula:

M₂ = (100)(0.15) / (150) = 0.1 M

  • Required volume of HCl of 0.05M HCl can be made by diluting 250 mL of 10 M HCl will be calculated by using the above formula:

V₂ = (10)(250) / (0.05) = 50,000 mL

  • Molarity of the resultant solution is:

M₂ = (1.5)(345) / (250) = 2.07 M

  • Required volume of water to add on KCl solution is:

V₂ = (2.4)(500) / (1) = 1,200 mL

Hence required values of molarity and volume are 2,100 mL, 0.75 M, 0.1 M, 50,000 mL, 2.07 M and 1,200 mL respectively.

To know more about molarity & volume, visit the below link:
https://brainly.com/question/27208890

#SPJ1

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for visiting IDNLearn.com. We’re here to provide clear and concise answers, so visit us again soon.