Get detailed and reliable answers to your questions on IDNLearn.com. Get prompt and accurate answers to your questions from our community of knowledgeable experts.

A +1.4 nC charge exerts a repulsive force of 20.0 mN on a second charge
which is located a distance of 2.2 m away from it. What is the magnitude
and sign of the second charge?


Sagot :

Answer:

+ .00769 C

Explanation:

Whoever 'katie' is , removed my previous, innocuous answer for some reason....

The force is repulsive , so the charge is also POSITIVE

f = k q1 q2 / r^2  

   k = Coulombs constant = 8.98755 x 10^9  kg m^3 . (s^2 C^2)

   q 1 = 1.4 x 10^-9 C     f = 20 x 10^-3  N

    r = 2.2 m       q2 = ?

Sub in the values to get q 2 = + .00769 C

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find the answers you need at IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.