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A 0.4 kg rock is dropped through a 6m height. Find its speed as it hits the ground. What is its speed at half way down?

Sagot :

Kaztralgamingidn

Answer:

83.1557575 M/s

Explanation:

V²=u²+2as

v=[tex] \sqrt{u ^{2} { + 2as}^{ } } [/tex]

u is initial velocity =0

here a =g

[tex]v = \sqrt{2gs} [/tex]

v=

[tex] \sqrt{2 \times 9.8 \times 6} [/tex]

v= 83.1557575 M/s

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