Connect with a community that values knowledge and expertise on IDNLearn.com. Discover reliable and timely information on any topic from our network of knowledgeable professionals.
Sagot :
(1) The number of moles of oxygen gas is 0.123 mole.
(2) The volume occupied by the nitrogen gas is 50.75 Liters.
(3) The pressure exerted by the CO2 gas is 28.7 atm
(4) The temperature of the Cl2 gas is -118.37⁰C
Number of moles of oxygen
The number of moles of oxygen occupied at the given condition is calculated as follows;
PV = nRT
n = PV/RT
where;
- T = 25ºC = 273 + 25 = 298K
- R is ideal gas constant = 0.08205 L.atm/mol.K
n = (2.5 x 1.2) / (0.08205 x 298)
n = 0.123 mol
Volume of the gas
PV = nRT
V = nRT/P
where;
- R = 62.36 L.mmHg/mol.K
V = (2 x 62.36 x 293) / (720)
V = 50.75 Liters
Pressure of the gas
PV = nRT
P = nRT/V
where;
- n is number of moles
Molar mass of CO2 = 44
n = 25/44 = 0.568
P = (0.568 x 0.08205 x 308)/(0.5)
P = 28.7 atm
Temperature of the gas
T = PV/nR
molar mass of Cl2 = 71 g
n = 5/71 = 0.07
T = (900 x 0.75)/(0.07 x 62.36)
T = 154.63 K
T = 154.63 - 273 = -118.37⁰C
Learn more about volume of gas here: https://brainly.com/question/25736513
#SPJ1
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for answers ends at IDNLearn.com. Thank you for visiting, and we hope to assist you again soon.